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Q.

Two vectors A→ and B→ have equal magnitudes. If magnitude of A→+B→ is equal to two times the magnitude of A→−B→, then the angle between  A→ and B→ will be :

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a

sin−1⁡13

b

cos−1⁡35

c

cos−1⁡13

d

sin−1⁡35

answer is C.

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Detailed Solution

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A→+B→=2A21+cosθ  

A→-B→=2A21-cosθ

given A→+B→=2A→-B→

2A21+cosθ2A21-cosθ=2

1+cosθ1-cosθ=4; cosθ=35

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