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Two vertical parallel glass plates are partially submerged in water. The distance between the plates is d and the length is l. Assume that the water between the plates does not reach the upper edges of the plates and that the wetting is complete. The water will rise to height ( $ρ$ density of water and $σ$ = surface tension of water)

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$\frac{5 σ}{ρgd}$

$\frac{4 σ}{ρgd}$

$\frac{σ}{2 ρgd}$

$\frac{2 σ}{ρgd}$

answer is A.

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Detailed Solution

Total upward force due to surface tension $= F_{B} = 2 σl - - - (1)$

Weight of lifted liquid $= mg = (hld) ρg - - - (2)$

Equating (1) & (2), we get $h = \frac{2 σ}{ρgd}$

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