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Two voltmeters $V_{r i g h t}$ and $V_{l e f t},$ each with an internal resistance of $10^{6} Ω$ are connected through wires of negligible resistance. The ‘+’ side of both voltmeters is up as shown in the figure. A changing magnetic field is present in the shaded region. At a particular moment in time $V_{r i g h t}$ reads $- 0.1 V .$ At the same moment, the reading of voltmeter $V_{l e f t}$ is

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0.2 V

– 0.2 V

0.1 V

– 0.1 V

answer is C.

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Detailed Solution

Both voltmeters have equal internal resistances, so both will have the same $0.1 V$ potential drop across themselves. The counter clockwise current enters the positive terminal of the left hand voltmeter, so it will read $+ 0.1 V .$

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