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Two waves A and B are of amplitudes 3 cm and 4 cm respectively. Compare their loudness. Which sound is louder ? Given, amplitude of A = 3 cm, amplitude of B = 4 cm

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B is louder

A & B Both are Louder

A & B Both are lesser Louder

A is louder

answer is B.

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Detailed Solution

$\frac{L o u d n e s s o f A}{L o u d n e s s o f b} = \frac{{(A m p l i t u d e o f A)}^{2}}{{(A m p l i t u d e o f b)}^{2}} \frac{{(3 c m)}^{2}}{{(4 c m)}^{2}} = \frac{9}{16} T h e s o u n d B l o u d e r t h a n A$

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