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Q.

Two waves are simultaneously passing through a string and their equations are:
y=A1sink(x-vt),y2=A2sink(x-vt+x0) . Given amplitudes  A1=12mm and A2=5mm, x0=3.5cm  and wave number  k=6.28cm-1 . The amplitude of the resulting wave will be __________mm.
 

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answer is 7.

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Detailed Solution

 y1=A1sink(xvt) y2=5sin6.28(xvt+3.5)
 
Phase difference,  Δϕ=k(Δx)=6.28×3.5=7π
 
 A2=A12+A22+2A1A2cosϕ A=(12)2+(5)2+2(12)(5)cos(7π) =144+25120=49=7mm
 
 

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