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Two wire A and B have equal lengths and are made of the same material, but the diameter of A is twice that of wire B. Then, for a given load.

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the extension of B will be four times that of A

the extension of A and B will be equal

the strain in B is four times that in A

the strains in A and B will be equal

answer is A, C.

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Detailed Solution

$e x t e n s i o n \propto \frac{1}{r^{2}}$

$s t r a i n \propto e x t e n s i o n$

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