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Two wires A & B are identical shape and size are stretched by same magnitude of force. Then extensions are found to be 0.2% and 0.5% respectively. The ratio of their young’s moduli is $\frac{20}{x} .$ Find ‘ $x$ ’ value

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answer is 8.

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Detailed Solution

$Y \propto \frac{1}{e} \Rightarrow \frac{Y_{1}}{Y_{2}} = \frac{e_{2}}{e_{1}} = \frac{0.5}{0.2} = \frac{5}{2} = \frac{20}{8}$

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