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Two wires are made of the same material and have the same volume. However, wire 1 has cross-sectional area A and wire 2 has cross-sectional area 3A. If the length of wire 1 increases by $Δ x$ on applying force F, how much force is needed to stretch wire 2 by the same amount?

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answer is B.

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Detailed Solution

$F = \frac{Y A e}{l} = \frac{Y A^{2} e}{V}$
$∴ \frac{F}{F^{1}} = \frac{A^{2}}{9 A^{2}} \Rightarrow F^{1} = 9 F$

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