Two wires made of same material have their length are in the ratio 1 : 2 and their masses in the ratio 3 : 16. The ratio of resistance of two wires is

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2 : 1

3 : 4

4 : 3

1 : 2

answer is D.

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Detailed Solution

$R = \frac{ρl}{A} = \frac{{ρl}^{2}}{Al} = \frac{{ρl}^{2} d}{m}$

as they are from same material density and specific resistance are same. $\frac{R_{1}}{R_{2}} = \frac{l_{1}^{2}}{l_{2}^{2}} \frac{m_{2}}{m_{1}} = \frac{1}{4} \frac{16}{3} = 4 : 3$

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