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Two women Shanti and Kamla of masses $50 kg$ and $60 kg$ respectively climb up through a height of $10 m$ . Shanti takes $20 s$ while Kamla takes $40 s$ to reach. The difference of power expended by Shanti and Kamla is [[1]] $W$ . (Take $g = 10 m / s^{2}$ )

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Detailed Solution

Two women Shanti and Kamla of masses

50 kg

and

60 kg

respectively climb up through a height of

10 m

. Shanti takes

20 s

while Kamla takes

40 s

to reach. The difference of power expended by Shanti and Kamla is

100 W .

Given:
Mass of shanti,

m_{s} = 50 kg

mass of kamla,

m_{k} = 60 kg

Height,

h = 10 m

time taken by shanti,

t_{s} = 20 s

time taken by kamla,

t_{k} = 40 s

we know power,

P = \frac{mgh}{t}

Let the power of shanti is

P_{s}

P_{S} = \frac{50 \times 10 \times 10}{20}

{\Rightarrow P}_{S}

= 250 W

Power of Kamla = P_{K} = \frac{60 \times 10 \times 10}{40}

\Rightarrow P_{K} = 150 W

Difference in power expended

= 250 - 150 = 100 W

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