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$T w o v e r t i c a l p o l e s a r e 150 m e t e r s a p a r t a n d t h e h e i g h t o f o n e i s t h r e e t i m e s t h a t o f t h e o t h e r$
$I f f r o m t h e m i d d l e p o i n t o f t h e l i n e j o i n i n g t h e i r f e e t,$
$a n o b s e r v e r f i n d s t h e a n g l e s o f e l e v a t i o n o f t h e i r t o p s t o b e c o m p l i m e n t a r y$
$t h e n t h e h e i g h t o f t h e s h o r t e r p o l e i s$

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$30$

$20 \sqrt{3}$

$25$

$25 \sqrt{3}$

answer is D.

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Detailed Solution

$W e h a v e \tan θ = \frac{h}{75} = \frac{75}{3 h}$

$\Rightarrow h^{2} = \frac{{(75)}^{2}}{3}$

$\Rightarrow h = 25 \sqrt{3} m$

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