u^1 and u^2 are two unit vectors such that |u^1×u^2|=3|u^1.u^2|. Then |u^1+u^2| is

|u^1×u^2|=3|u^1.u^2|⇒1.1sin⁡θ=3.1.1.cos⁡θ∴ θ=60o=Angle between u^1 and u^2∴ |u^1+u^2|=12+12+2.1.1.cos⁡60o=3

u^1 and u^2 are two unit vectors such that |u^1×u^2|=3|u^1.u^2|. Then |u^1+u^2| is

|u^1×u^2|=3|u^1.u^2|⇒1.1sin⁡θ=3.1.1.cos⁡θ∴ θ=60o=Angle between u^1 and u^2∴ |u^1+u^2|=12+12+2.1.1.cos⁡60o=3

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${\hat{u}}_{1} and {\hat{u}}_{2}$ are two unit vectors such that $| {\hat{u}}_{1} \times {\hat{u}}_{2} | = \sqrt{3} | {\hat{u}}_{1} . {\hat{u}}_{2} |$ . Then $| {\hat{u}}_{1} + {\hat{u}}_{2} |$ is

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$\sqrt{2}$

$\sqrt{2 + \sqrt{3}}$

$\sqrt{3}$

answer is C.

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$| {\hat{u}}_{1} \times {\hat{u}}_{2} | = \sqrt{3} | {\hat{u}}_{1} . {\hat{u}}_{2} | \Rightarrow 1.1 \sin θ = \sqrt{3} .1.1. \cos θ$

$∴ θ = 60^{o} =$ Angle between ${\hat{u}}_{1} and {\hat{u}}_{2}$

$∴ | {\hat{u}}_{1} + {\hat{u}}_{2} | = \sqrt{1^{2} + 1^{2} + 2.1.1. \cos 60^{o}} = \sqrt{3}$

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u^1 and u^2 are two unit vectors such that |u^1×u^2|=3|u^1.u^2|. Then |u^1+u^2| is

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${\hat{u}}_{1} and {\hat{u}}_{2}$ are two unit vectors such that $| {\hat{u}}_{1} \times {\hat{u}}_{2} | = \sqrt{3} | {\hat{u}}_{1} . {\hat{u}}_{2} |$ . Then $| {\hat{u}}_{1} + {\hat{u}}_{2} |$ is