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Ultrasonic signal sent from SONAR returns to it after reflection from a rock after a lapse of 1 sec. If the velocity of ultrasound in water is 1600 ms^–1, the depth of the rock in water is

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300 m

800 m

400 m

500 m

answer is D.

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Detailed Solution

If d is the distance of rock from SONAR then
$2 d = vt \Rightarrow d = \frac{v \times t}{2} = \frac{1600 \times 1}{2} = 800 m$

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