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Un polarized light passes through a polarizer and analyzer which are at an angle of $45^{0}$ with respect to each other. The intensity of polarized light coming from analyzer is $5 W / m^{2}$ .The intensity of unpolarised light incident on polarizer is

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$10 W / m^{2}$

$20 W / m^{2}$

$5 \sqrt{3} W / m^{2}$

$5 \frac{\sqrt{3}}{4} W / m^{2}$

answer is C.

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Detailed Solution

Intensity of polarized light $I = 5 W m^{- 2}$

Angle $θ = 45^{0}$

Intensity of polarized light after passing through the analyser

$I = \frac{I_{0}}{2} \cos^{2} θ$

$5 = \frac{I_{0}}{2} \cos^{2} 45$

$5 = \frac{I_{0}}{2} . \frac{1}{2}$

$I_{0} = 20 W / m^{2}$

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