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Uncertainity in position of a minute particle of mass 25g in space is $10^{- 5} m$ . What is the uncertainity in its velocity (in $m s^{- 1}$ ) ?
$(6.6 \times 10^{- 34} Js)$

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$0.5 \times 10^{- 34}$

$2.1 \times 10^{- 34}$

$2.1 \times 10^{- 28}$

$0.5 \times 10^{- 23}$

answer is C.

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Detailed Solution

\large \Delta v = \frac{h}{{4\pi m}} \times \frac{1}{{\Delta x}} \

\large \ = \frac{{6.625 \times 1{0^{ - 34}}}}{{4 \times 3.14 \times 25 \times 1{0^{ - 3}}}} \times \frac{1}{{1{0^{ - 5}}}}\

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