Uncertainity in position of an electron (mass = 9.1×10−28g) moving with velocity of 3×104 cm/s accurate up to 0.001% will be Use h/4π in uncertainity expression where h=6.626×10−27 erg−s)

Δ v=3×104×0.001100 cm/second Δ x=h4πmΔv=6.6×10−34J−s4×3.14×9.1×10−28×0.001100×3×104=1.93 cm

Uncertainity in position of an electron (mass = 9.1×10−28g) moving with velocity of 3×104 cm/s accurate up to 0.001% will be Use h/4π in uncertainity expression where h=6.626×10−27 erg−s)

Δ v=3×104×0.001100 cm/second Δ x=h4πmΔv=6.6×10−34J−s4×3.14×9.1×10−28×0.001100×3×104=1.93 cm

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Uncertainity in position of an electron (mass = $9 .1 \times 10^{- 28} g$ ) moving with velocity of $3 \times 10^{4} cm / s$ accurate up to 0.001% will be $(Use h / (4 π))$ in uncertainity expression where $h = 6 .626 \times 10^{- 27} erg - s$ )

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5.76 cm

7.68 cm

1.93 cm

3.84 cm

answer is C.

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$Δ v = \frac{3 \times 10^{4} \times 0 .001}{100} cm / second Δ x = \frac{h}{4 π m Δ v} = \frac{6 .6 \times 10^{- 34} J - s}{4 \times 3 .14 \times 9 .1 \times 10^{- 28} \times \frac{0 .001}{100} \times 3 \times 10^{4}} = 1 .93 cm$

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Uncertainity in position of an electron (mass = 9.1×10−28g) moving with velocity of 3×104 cm/s accurate up to 0.001% will be Use h/4π in uncertainity expression where h=6.626×10−27 erg−s)

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Uncertainity in position of an electron (mass = $9 .1 \times 10^{- 28} g$ ) moving with velocity of $3 \times 10^{4} cm / s$ accurate up to 0.001% will be $(Use h / (4 π))$ in uncertainity expression where $h = 6 .626 \times 10^{- 27} erg - s$ )