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Uncertainity in the position of an electron(mass = 9.1 × 10–31 kg) moving with a velocity 300 m.s^–1, accurate upto 0.001%, will be (h = 6.63 × 10^–34 J.S)

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19.2 × 10^–2 m

5.76× 10^–2 m

3.82× 10^–2 m

1.92 × 10^–2 m

answer is C.

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Detailed Solution

$∆ x . ∆ p \geq \frac{h}{4 π} ∆ x \geq \frac{6.626 X 10^{- 34}}{4 \times 3.14 \times 9.1 \times 10^{- 31} \times 300 \times 0.001 \times 10^{- 2}} = 0.01933 m$

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