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Uncertainty in finding the position of a particle of mass $10^{- 30} g$ is 0.0527 cm. Uncertainty in finding the velocity of the particle is

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$10^{- 8} cm / s$

$10^{- 6} cm / s$

$10^{4} cm / s$

$10^{9} cm / s$

answer is C.

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Detailed Solution

$Δ V = \frac{h}{4 π m} \times \frac{1}{Δ x} = \frac{6.625 \times 10 e r g . s e c}{4 \times 3.14 \times 10^{- 30} g} \times \frac{1}{0.527 cm}$

$= \frac{0.527 \times 10^{- 27}}{0.0527 \times 10^{- 30}} = 10^{4} cm / s$

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