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Q.

Uncertainty in position of a hypothetical subatomic particle is $1 Å$ and uncertainty in velocity is $3.3 / 4 π \times 10^{5} m / s$ then the mass of the particle is approximately $(h = 6.6 \times 10^{- 34} J s) :$

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a

$2 \times 10^{- 28} kg$

b

$4 \times 10^{- 29} kg$

c

$2 \times 10^{- 29} kg$

d

$2 \times 10^{- 27} kg$

answer is C.

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Detailed Solution

$m = \frac{h}{4 π ΔVΔX}$

$m = \frac{6.6 \times 10^{- 34}}{4 \times π \times 1 \times 10^{- 10} \times \frac{3.3}{4 π} \times 10^{5}}$

$m = 2 \times 10^{- 29} kg$

Hence, option C is correct.

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