Under a constant pressure head, the rate of streamlined volume flow of a liquid through a capillary tube is $Q$ . If the length of the capillary tube is doubled and the diameter of the bore is halved, the rate of flow would become

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Q / 4

Q / 32

Q / 8

Q / 16

answer is D.

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Detailed Solution

The rate of flow is given by
$Q = \frac{π P r^{4}}{8 η l}$
If l is doubled and r is halved, the rate of flow will become ${(\frac{1}{2})}^{4} \times \frac{Q}{2} = \frac{Q}{32}$ .

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