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Q.

Under critical states of a gas for one mole of a gas, compressibility factor is

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a

1

b

$\frac{3}{8}$

c

$\frac{8}{3}$

d

$\frac{1}{4}$

answer is A.

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Detailed Solution

$V_{C} = 3 b P_{C} = a / 27 b^{2} T_{C} = 8 a / 27 Rb Z_{C} = \frac{P_{C}}{T_{C}} = \frac{(a / 27 b^{2}) (3 b)}{R (8 a / 27 Rb)} = \frac{3}{8}$

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