Under isothermal conditions, a gas at 300 K expands from 0.1 L to 0.25 L against a constant external pressure of 2 bar. The work done by the gas is [Given that 1 L bar =100 J]

Expansion of a gas against a constant external pressure is an irreversible process. The work done in an irreversible process

Work done by the gas is 30 J

$$\begin{gathered} =P_{\mathrm{ext}}\Delta V=P_{\mathrm{ext}}\left(V_2-V_1\right)=2(0.25-0.1) \\ =2\times 0.15 \mathrm{Lbar}=0.30\times 100 \mathrm{J}=30 \mathrm{J}9100007383 \end{gathered}$$