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Q.

Under the same load, wire A having length 5.0 m and cross section 2.5×105m2 stretches uniformly by the same amount as another wire B of length 6.0 m and a cross section of 3.0×105m2 stretches. The ratio of the Young’s modulus of wire A to that of wire B will be:

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a

1:1

b

1:10

c

1: 4

d

1: 2

answer is B.

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Detailed Solution

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Y=Fℓle
Extension and forces acting are same
yA
yAyB=AB×ABAA=56×3×1052.5×105yAyB=11:1

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