Unlike ${PbCl}_{4}, {PI}_{4} and {PBr}_{4}$ are not found because

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larger iodine and bromine are able to reduce ${Pb}^{4 +}$ to ${Pb}^{2 +}$ or Pb.

bromine and iodine are more electronegative than chlorine.

the statement is incorrect

iodine and bromine are smaller in size.

answer is C.

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Detailed Solution

${Pb}^{4 +}$ has higher polarizing power and ${Br}^{-} and I^{-}$ being larger in size can easily give the electrons to ${Pb}^{4 +}$ , i.e., as compared to ${Cl}^{-}, {Br}^{-} and I^{-}$ are good reducing agents.

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