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Q.

Upon heating, the length of the side of a cube change by 2%. The volume of the cube changes by

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a

0.5%

b

4%

c

6%

d

1%

answer is B.

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Detailed Solution

Percentage change in length $\frac{Δ l}{l} \times 100 = 2 %$

We have percentage change in volume

$\frac{Δ V}{V} \times 100 = 3 (\frac{Δ l}{l} \times 100)$

$= 3 (2) = 6 %$

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