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Upon heating, the length of the side of a cube changes by 2%. The volume of the cube changes by

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Detailed Solution

% change in length $\frac{∆ l}{l} x 100 = 2 %$
we have % change in volume
$\frac{∆ V}{V} x 100 = 3 (\frac{∆ l}{l} x 100) = 3 (2) = 6 %$

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