Upon heating with ${\mathrm{Cu}}_2\mathrm{S}$, the reagent(s) that give copper metal is/ are :

Upon heating with ${\mathrm{Cu}}_2\mathrm{S}$ the reagent(s) that give copper metal  is  $\mathrm{CuO}, {\mathrm{Cu}}_2\mathrm{O}$ and ${\mathrm{CuSO}}_4$

$2{\mathrm{CuFeS}}_2+{\mathrm{O}}_2\stackrel{\mathrm{\Delta }}{\to }{\mathrm{Cu}}_2\mathrm{S}+2\mathrm{FeS}+{\mathrm{SO}}_2$

(B) $4\mathrm{CuO}\stackrel{{1100}^{\circ }\mathrm{C}}{⟶}2{\mathrm{Cu}}_2\mathrm{O}+{\mathrm{O}}_2$

$2{\mathrm{Cu}}_2\mathrm{O}+{\mathrm{Cu}}_2\mathrm{S}\stackrel{\mathrm{\Delta }}{\to }6\mathrm{Cu}+{\mathrm{SO}}_2$

(C) ${\mathrm{Cu}}_2\mathrm{S}+2{\mathrm{Cu}}_2\mathrm{O}\stackrel{\mathrm{\Delta }}{\to }6\mathrm{Cu}+{\mathrm{SO}}_2$

(D) ${\mathrm{CuSO}}_4\stackrel{{720}^{\circ }\mathrm{C}}{\to }\mathrm{CuO}+{\mathrm{SO}}_2+\frac{1}{2}{\mathrm{O}}_2$

$\begin{array}{l}4\mathrm{CuO}\stackrel{{1100}^{\circ }\mathrm{C}}{\to }2{\mathrm{Cu}}_2\mathrm{O}+{\mathrm{O}}_2\\ 2{\mathrm{Cu}}_2\mathrm{O}+{\mathrm{Cu}}_2\mathrm{S}\stackrel{\mathrm{\Delta }}{\to }6\mathrm{Cu}+{\mathrm{SO}}_2\end{array}$

Hence, options B, C and D are correct.