Uranium-235 is used as fuel in a nuclear reactor that takes 30 days to use up 2 kg of fuel. If each fission gives 185 MeV of usable energy, then the power output of the reactor is

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Uranium-235 is used as fuel in a nuclear reactor that takes 30 days to use up 2 kg of fuel. If each fission gives 185 MeV of usable energy, then the power output of the reactor is

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5850 MW

5.85 MW

585 MW

58.5 MW

answer is B.

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Detailed Solution

Amount of uranium used per sec

$\frac{2 \times 10^{3}}{30 \times 24 \times 60 \times 60} = 7.72 \times 10^{- 4} g m / s e c$

No fission per sec=

$\frac{7.72 \times 10^{- 4}}{235} \times 6 \times 10^{23} = 1.97 \times 10^{18}$

Power of reactor

$P = 1.97 \times 10^{18} \times 185 \times 10^{- 13} \times 1.6 = 58.5 MW$

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