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Q.

Use the given algebraic expression to complete the table of number patterns.

S. No.ExpressionTerms
1st 2nd3rd4th5th...10th...100th...
(i)2n - 113579-19---
(ii)3n + 2581114------
(iii)4n + 1591317------
(iv)7n + 2027344148------
(v)n + 1251017----10001-

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Detailed Solution

(i) From the table for the given expression, (2n – 1)

we need to find 100th term,

So n = 100

= (2 × 100) – 1

= 200 – 1

= 199

(ii) From the table for the given expression, (3n + 2)

we need to find 5th term,

So, n = 5

= (3 × 5) + 2

= 15 + 2

= 17

Next, we need to find 10th term,

So, n = 10

= (3 × 10) + 2

= 30 + 2

= 32

Next, we need to find 100th term,

So, n = 100

= (3 × 100) + 2

= 300 + 2

= 302

(iii) From the table for the given expression, (4n + 1)

we need to find 5th term,

So, n = 5

= (4 × 5) + 1

= 20 + 1

= 21

Next, we need to find 10th term,

So, n = 10

= (4 × 10) + 1

= 40 + 1

= 41

Next, we need to find 100th term,

So, n = 100

= (4 × 100) + 1

= 400 + 1

= 401

(iv) From the table for the given expression, (7n + 20)

we need to find 5th term,

So, n = 5

= (7 × 5) + 20

= 35 + 20

= 55

Next, we need to find 10th term,

So, n = 10

= (7 × 10) + 20

= 70 + 20

= 90

Next, we need to find 100th term,

So, n = 100

= (7 × 100) + 20

= 700 + 20

= 720

(v) From the table for the given expression, (n2 + 1)

we need to find 5th term,

So, n = 5

= (52) + 1

= 25+ 1

= 26

Next, we need to find 10th term,

So, n = 10

= (102) + 1

= 100 + 1

= 101

So the complete table is:

S. No.ExpressionTerms
1st 2nd3rd4th5th...10th...100th...
(i)2n - 113579-19-199-
(ii)3n + 258111417-32-302-
(iii)4n + 159131721-41-401-
(iv)7n + 202734414855-90-720-
(v)n + 125101726-101-10001-
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