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Using a bar magnet P, a vibration magnetometer has time period 2 seconds. When a bar Q (identical to p in mass and size) is placed on top of P, the time period is unchanged. Which of the following statements is true?

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Q is of non-magnetic material.

Q is a bar magnet identical to P, and its north pole placed on top of P's north pole.

Q is of unmagnetized ferromagnetic material.

Nothing can be said about Q's properties.

answer is B.

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Detailed Solution

$T = 2 π \sqrt{\frac{I}{{MB}_{H}}} .$

If Q is an identical bar magnet, then time period of system will be

$T' = 2 π \sqrt{\frac{2 I}{(2 M) B_{H}}} = T$

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