Using Euclid’s division algorithm, the HCF of 4407, 2938 and 1469 is ____.

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Detailed Solution

Using Euclid’s division algorithm, the HCF of 4407, 2938 and 1469 is 1469.
Given 3 numbers 4407, 2938 and 1469.
Applying Euclid’s division Lemma,
Assume a = 4407 and b = 2938,

4407 = 2938 × 1 + 1469 H e r e, r = 1469 ≠ 0.

So, Dividend = 2938 and divisor = 1469.
Applying Euclid’s division Lemma,
Assume a = 2938 and b = 1469,

2938 = 1469 × 2 + 0 H e r e, r = 0.

HCF of 4407 and 2938 is 1469.
Applying Euclid’s division Lemma,
Assume a = 1469 and b = 1469,

1469 = 1469 × 1 + 0

The final value is 1469.
Hence, the H.C.F of given numbers is 1469.

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