Using light of wavelength 6000 Ao stopping potential is obtained 2.4 volt for photoelectric cell. If light of wavelength 4000 Ao is used, then stopping potential (in volt) would be(Round off to nearest integer)

eV=hν-ϕe2.4=124006000-ϕ...........(1)eV=124004000-ϕ.............(2)After solving (1) and (2) we get,V=3.43 volt

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Using light of wavelength 6000 $\overset{o}{A}$ stopping potential is obtained 2.4 volt for photoelectric cell. If light of wavelength 4000 $\overset{o}{A}$ is used, then stopping potential (in volt) would be
(Round off to nearest integer)

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answer is 3.

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$eV = hν - ϕ$

$e 2.4 = \frac{12400}{6000} - ϕ . . . . . . . . . . . (1)$

$eV = \frac{12400}{4000} - ϕ . . . . . . . . . . . . . (2)$

After solving (1) and (2) we get,

$V = 3.43 volt$

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