‘V’ litres of 0.333 M KMnO₄ can completely oxidize 5 litres of 0.5 M H₂O₂ in faint alkaline medium. The value of ‘V’ is

n-factor of KMnO₄ in faint alkaline medium is 3 ;

n-factor of H₂O₂ in faint alkaline medium is 2 ;

V₁N₁(KMnO₄)=V₂N₂(H₂O₂) ;

V₁(n₁)M₁=V₂(n₂)M₂ ;

V(3)0.333=5(2)0.5 ; 

V= 5 litres ;