$V_2{O}_5$ reacts with alkalies and acids to give ‘X’ and ‘Y’ respectively, which are

V₂O₅ is amphoteric in nature so it can react with both acid and base.

$V_2{O}_5 +6 NaOH \to 2N{a}_{3}V{O}_4 +3H_{2}O$

${\mathrm{V}}_2{\mathrm{O}}_5+ {\mathrm{H}}_2{\mathrm{SO}}_4 \to 2{\mathrm{VOSO}}_4+ {\mathrm{H}}_2\mathrm{O}$

Correct answer is  VO₄^3−​ and VO²⁺