Value of Kp for the equilibrium reaction N2O4 →2NO2 at 288 K is 47.9. The Kc for this reaction at same temperature is

KC =KpRT =47.90.083×288 =2Hence, the correct answer 2.

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Value of Kp for the equilibrium reaction $N_{2} O_{4} \to 2 N O_{2}$ at 288 K is 47.9. The Kc for this reaction at same temperature is

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answer is 2.

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$K_{C} = \frac{K_{p}}{R T} = \frac{47.9}{0.083 \times 288} = 2$

Hence, the correct answer 2.

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