Value of ‘R’ in SI units

Ideal gas equation is

PV=nRT

$\mathrm{R}=\frac{\mathrm{pv}}{\mathrm{nT}}$

Consider if volume, V in lit and pressure, P in kPa , then the units of R will be as given below

$\mathrm{R}=\frac{101.3\mathrm{kpa}\times 22.4\mathrm{L}}{1 \mathrm{mol}\times 273 \mathrm{k}}=8.314 \mathrm{kpa}.\mathrm{L} {\mathrm{mol}}^{-1}, {\mathrm{K}}^{-1}$

But we know that PV is equal to work done per mole. Kelvin

So that k Pa.L = Joule

Hence, the gas constant ‘R’ value is equal to$8.314 \mathrm{J} {\mathrm{mol}}^{-1}, {\mathrm{K}}^{-1}$(SI unit)