Value of a→×b→,a→×c→,d→ is equal to

a×b×(a×c)·d a b ca-0·d=a b c (a·d)

Value of a→×b→,a→×c→,d→ is equal to

a×b×(a×c)·d a b ca-0·d=a b c (a·d)

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Value of $[\vec{a} \times \vec{b}, \vec{a} \times \vec{c}, \vec{d}]$ is equal to

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$(\vec{a} . \vec{d}) [\vec{a} \vec{b} \vec{c}]$

$(\vec{a} . \vec{c}) [\vec{a} \vec{b} \vec{c}]$

$(\vec{a} . \vec{b}) [\vec{a} \vec{b} \vec{c}]$

$2 (\vec{a} . \vec{d}) [\vec{a} \vec{b} \vec{c}]$

answer is A.

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$((a \times b) \times (a \times c)) \cdot d ([a b c] a - 0) \cdot d = [a b c] (a \cdot d)$

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Value of a→×b→,a→×c→,d→ is equal to

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Value of $[\vec{a} \times \vec{b}, \vec{a} \times \vec{c}, \vec{d}]$ is equal to