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Q.

Values of x and y satisfying the equation sin7y=|x3x29x+9|+|x3x24x+4|+sec22y+cos4y  are 
 

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a

x=1,y=nπ,nI

b

x=1,y=2nπ+π2,nI

c

x=1,y=2nπ,nI

d

x=2,y=nπ16,nI

answer is B.

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Detailed Solution

sin7y=|x3x29x+9|+|x3x24x+4|+sec22y+cos4y For  x=1,sin7y=sec22y+cos4y sin7ycos22y=1+cos4ycos22y Since, LHS 1. and RHS 1.  which is possible only when    sin7ycos22y=1 sin7y=1  and  cos22y=1;  y=π2

General value of y  is 2nπ+π2 
Hence,  x=1  and  y=2nπ+π2,nI

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Values of x and y satisfying the equation sin7y=|x3−x2−9x+9|+|x3−x2−4x+4|+sec22y+cos4y  are