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Van’t Hoff factor for 0.001 M aqueous acetic acid solution is 1.1. The pH of the solution is

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3.4

4.5

answer is C.

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Detailed Solution

$i = 1 + α (n - 1) . . (n = 2) 1.1 = 1 + α α = 0.1$

$[H^{+}] = Cα = 0.001 (0.1) = 1 \times 10^{- 4} pH = - \log [H^{+}] = - \log [1 \times 10^{- 4}] pH = 4$

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