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Q.

Van't Hoff factor of 70% dissociated MgCl2 solution is

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a

2.4

b

1.7

c

2.7

d

2.05

answer is C.

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Detailed Solution

Examples…..M2SO4(Na2SO4, K2SO4 etc), M2CO3(Na2CO3, K2CO3 etc) ;

They all are classified as ‘A2B’ type electrolytes…..A2B 2A++B2- ; n=3

                     Van't Hoff factor, i = 1-α+ ;

    when n= 3 

                    Van't Hoff factor, i = 1+2α ; 

n=3….for AB2(bi-univalent electrolyte)…...AB2 A2++2B- ; n=3

Examples…..MX2(BaCl2, CaCl2 etc), M(NO3)2 (Ba(NO3)2, Ca(NO3)2 etc)

α= Degree of ionization  (or) dissociation ;

Ex ; For 5% ionized electrolyte  α=5100= 0.05 ;

0.1, 0.15, 0.2, 0.25, 0.3…..for 10%, 15%, 20%, 25%, 30% ionized electrolyte

α for x% electrolyte = x100

For AB2 or A2B type : i= 1+2α ;

i= a) 1.1….5% ionized  b) i= 1.2…..10% ionized c) i=1.3….15% ionized d) i= 1.4…..20% ionized…..

Hint: For every 5% increase in ionization i.e for every 0.05 units increase in 'α' value ‘i’ increases by 0.1 units ;

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