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Q.

Van’t Hoff factor of ${Hg}_{2} {Cl}_{2}$ in its aqueous solution will be: $({Hg}_{2} {Cl}_{2}$ is 80% ionized in the solution)

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a

3.6

b

4.6

c

1.6

d

2.6

answer is B.

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Detailed Solution

${Hg}_{2} {Cl}_{2} \underset{n = 3}{⇌} {Hg}_{2}^{2 +} + 2 {Cl}^{-}$

$α = \frac{i - 1}{n - 1}; 0.8 = \frac{i - 1}{3 - 1}; i = 2.6$

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