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Vapour density of an organic compound is 23. It contains 52.17% of carbon and 13% of hydrogen. The compound gives iodoform test. The compound is :

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ethanol

dimethyl ether

acetone

methanol

answer is A.

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Detailed Solution

Element	Carbon	Hydrogen	Oxygen
no. of moles	$\frac{52.17}{12} = 4.34$	$\frac{13}{1}$ =13	$\frac{34.83}{16} = 2.17$
Relative ratios	$\frac{4.34}{2.17} = 2$	$\frac{13}{2.17} = 6$	$\frac{2.17}{2.17} = 1$

Empirical formula is C₂H₆O.

The molar mass = 2× vapour density

=2×23 = 46

The compound is C₂H₅OH.

That is ethanol since it gives positive iodoform test.

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