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Q.

Vapour pressure of a pure liquid X is 2 atm at 300 K. it is lowered to 1 atm on dissolving 1 g of Y in 20 g of liquid x. If molar mass of X is 200, what is the molar mass of Y?

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a

100

b

50

c

200

d

20

answer is A.

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Detailed Solution

po−pApAo=nBnA

2−12=WBMBXMAWA⇒12=1MBX20020

MB=200X220=20

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