Vapour pressure of CCl4 at 25oC is 143 mm of Hg 0.5 gm of a non-volatile solute (mol. wt.=65) is dissolved in 100 mlCCl4. Find the vapour pressure of the solution: (Density of CCl4 = 1.58 g / cm2)

P0-PsP0=w×MmW=143-0.5×15465×158×143 =143-1.03=141.97 mm.

Vapour pressure of CCl4 at 25oC is 143 mm of Hg 0.5 gm of a non-volatile solute (mol. wt.=65) is dissolved in 100 mlCCl4. Find the vapour pressure of the solution: (Density of CCl4 = 1.58 g / cm2)

P0-PsP0=w×MmW=143-0.5×15465×158×143 =143-1.03=141.97 mm.

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Vapour pressure of CCl₄ at 25_oC is 143 mm of Hg 0.5 gm of a non-volatile solute (mol. wt.=65) is dissolved in 100 mlCCl₄. Find the vapour pressure of the solution: (Density of CCl₄= 1.58 g / cm²)

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199.34 mm

141.43 mm

143.99 mm

94.39 mm

answer is A.

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Detailed Solution

$\frac{P^{0} - Ps}{P^{0}} = \frac{w \times M}{mW} = 143 - \frac{0.5 \times 154}{65 \times 158} \times 143 = 143 - 1.03 = 141.97 mm .$

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Vapour pressure of CCl4 at 25oC is 143 mm of Hg 0.5 gm of a non-volatile solute (mol. wt.=65) is dissolved in 100 mlCCl4. Find the vapour pressure of the solution: (Density of CCl4 = 1.58 g / cm2)

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Vapour pressure of CCl₄ at 25_oC is 143 mm of Hg 0.5 gm of a non-volatile solute (mol. wt.=65) is dissolved in 100 mlCCl₄. Find the vapour pressure of the solution: (Density of CCl₄= 1.58 g / cm²)