Vapour pressure of water at 293K is 17.535mm Hg. Calculate the vapour pressure of the solution at 293K when 25g of glucose is dissolved in 450g of water.

Glucose(solute)                                               Solvent(water)
w = 25g                                                               W = 450g
m = 180                                                                M = 18
$\begin{array}{l}\therefore {\mathrm{P}}_0=17.535\mathrm{mm}{\mathrm{P}}_{\mathrm{S}}=?\\ \frac{{\mathrm{P}}_0-{\mathrm{P}}_{\mathrm{S}}}{{\mathrm{P}}_0}=\frac{\mathrm{w}}{\mathrm{m}}\times \frac{\mathrm{M}}{\mathrm{W}}\\ \frac{17.535-{\mathrm{P}}_{\mathrm{S}}}{17.535}=\frac{25}{180}\times \frac{18}{450}\\ \therefore {\mathrm{P}}_{\mathrm{S}}=17.44\mathrm{mm}\cdot \mathrm{Hg}\end{array}$