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Q.

Vapour pressure of water at $293 K$ is $17.54 mm$ $Hg$ and the vapour pressure of a solution of 108 g of a compound in 1000 g of water at the same temperature is 17.34 mm Hg. Molecular mass of the compound is(round off the answer to two digits after the decimal)

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answer is 170.49.

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Detailed Solution

$x_{B} = \frac{p^{\circ} - p_{s}}{p^{\circ}}$

or $\frac{W_{B} M_{A}}{M_{B} W_{A}} = \frac{p^{\circ} - p_{s}}{p^{\circ}}$

or $\frac{108 \times 18}{1000 \times M_{B}} = \frac{17 .54 - 17 .34}{17 .54}$

Thus, $M_{B} = 170 .49$

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