Variation of potential V with r and field E with r for a point charge ‘Q’ is shown in the graph then

For a point charge at a distance of r.

The electric field is given by $\mathrm{E}=\frac{1}{4{\mathrm{\pi \epsilon }}_{\mathrm{o}}}\frac{\mathrm{Q}}{{\mathrm{r}}^2}\Rightarrow \mathrm{E}\propto \frac{1}{{\mathrm{r}}^2}$

The potential is given by $\mathrm{V}=\frac{1}{4{\mathrm{\pi \epsilon }}_{\mathrm{o}}}\frac{\mathrm{Q}}{\mathrm{r}}\Rightarrow \mathrm{V}\propto \frac{1}{\mathrm{r}}$

So, a small variation in the value of 'r' will result in higher change in E when compared to V.

So (1) is potential and (2) is field.