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Velocity and acceleration vectors of charged particle moving perpendicular to the direction of magnetic field at a given instant of time are $\vec{ϑ} = 2 \hat{i} + c \hat{j} and \bar{a} = 3 \hat{i} + 4 \hat{j}$ respectively. Then the value of ‘c’ is

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1.5

- 1.5

- 3

answer is C.

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Detailed Solution

\vec{v} . \vec{a} = 0

(As

\vec{v} & \vec{a}

are perpendicular then

\vec{v} . \vec{a} = 0

)

$(2 \hat{i} + C \hat{j}) . (3 \hat{i} + 4 \hat{j}) = 0$

$= 6 + 4 C = 0$

$4 C = - 6$

$C = \frac{- 6}{4} = \frac{- 3}{2}$

$C = - 1.5$

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