Velocity-displacement graph of a particle moving along a straight line is as shown. Line PB is normal to the curve and line PA is perpendicular to s-axis. The acceleration of the particle at P is

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$1 m / s^{2}$

$2 m / s^{2}$

$3 m / s^{2}$

Zero

answer is B.

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Detailed Solution

$a = v \frac{d v}{d x} = v \times slope of v - s l o p e = v \times \frac{- 1}{slope of normal curve} = 4 \times \frac{- 1}{(\frac{- 4}{1})} = 1 m s^{- 1}$

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