Velocity of a particle of mass 2 kg changes from  ${\overrightarrow{V}}_1=-2\widehat{i}-2\widehat{j}m/s$ to ${\overrightarrow{V}}_2=\widehat{i}-\widehat{j}m/s$  after colliding with a plane friction less surface. Choose the correct  option(s) regarding this collision:

A) The angle made by the plane surface with the positive x-axis is ${90}^0+{\tan }^{-1}\left(\frac{1}{3}\right)$

The angle made by the plane surface with the positive x-axis is  ${\tan }^{-1}\left(\frac{1}{3}\right)$

The direction of change in momentum of the particle makes an angle ${\tan }^{-1}\left(\frac{1}{3}\right)$ with the positive x-axis.

The direction of change in momentum of the particle makes an angle  ${90}^0+{\tan }^{-1}\left(\frac{1}{3}\right)$ with the plane surface.